What are the numbers divisible by 944?

944, 1888, 2832, 3776, 4720, 5664, 6608, 7552, 8496, 9440, 10384, 11328, 12272, 13216, 14160, 15104, 16048, 16992, 17936, 18880, 19824, 20768, 21712, 22656, 23600, 24544, 25488, 26432, 27376, 28320, 29264, 30208, 31152, 32096, 33040, 33984, 34928, 35872, 36816, 37760, 38704, 39648, 40592, 41536, 42480, 43424, 44368, 45312, 46256, 47200, 48144, 49088, 50032, 50976, 51920, 52864, 53808, 54752, 55696, 56640, 57584, 58528, 59472, 60416, 61360, 62304, 63248, 64192, 65136, 66080, 67024, 67968, 68912, 69856, 70800, 71744, 72688, 73632, 74576, 75520, 76464, 77408, 78352, 79296, 80240, 81184, 82128, 83072, 84016, 84960, 85904, 86848, 87792, 88736, 89680, 90624, 91568, 92512, 93456, 94400, 95344, 96288, 97232, 98176, 99120

There is a total of 105 numbers (up to 100000) that are divisible by 944.
The sum of these numbers is 5253360.
The arithmetic mean of these numbers is 50032.

How to find the numbers divisible by 944?

Finding all the numbers that can be divided by 944 is essentially the same as searching for the multiples of 944: if a number N is a multiple of 944, then 944 is a divisor of N.

Indeed, if we assume that N is a multiple of 944, this means there exists an integer k such that:

$k \times 944 = N$

Conversely, the result of N divided by 944 is this same integer k (without any remainder):

$k = \frac{N}{944}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 944 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 944 less than 100000):

1 × 944 = 944
2 × 944 = 1888
3 × 944 = 2832
...
104 × 944 = 98176
105 × 944 = 99120