What are the numbers divisible by 946?

946, 1892, 2838, 3784, 4730, 5676, 6622, 7568, 8514, 9460, 10406, 11352, 12298, 13244, 14190, 15136, 16082, 17028, 17974, 18920, 19866, 20812, 21758, 22704, 23650, 24596, 25542, 26488, 27434, 28380, 29326, 30272, 31218, 32164, 33110, 34056, 35002, 35948, 36894, 37840, 38786, 39732, 40678, 41624, 42570, 43516, 44462, 45408, 46354, 47300, 48246, 49192, 50138, 51084, 52030, 52976, 53922, 54868, 55814, 56760, 57706, 58652, 59598, 60544, 61490, 62436, 63382, 64328, 65274, 66220, 67166, 68112, 69058, 70004, 70950, 71896, 72842, 73788, 74734, 75680, 76626, 77572, 78518, 79464, 80410, 81356, 82302, 83248, 84194, 85140, 86086, 87032, 87978, 88924, 89870, 90816, 91762, 92708, 93654, 94600, 95546, 96492, 97438, 98384, 99330

There is a total of 105 numbers (up to 100000) that are divisible by 946.
The sum of these numbers is 5264490.
The arithmetic mean of these numbers is 50138.

How to find the numbers divisible by 946?

Finding all the numbers that can be divided by 946 is essentially the same as searching for the multiples of 946: if a number N is a multiple of 946, then 946 is a divisor of N.

Indeed, if we assume that N is a multiple of 946, this means there exists an integer k such that:

$k \times 946 = N$

Conversely, the result of N divided by 946 is this same integer k (without any remainder):

$k = \frac{N}{946}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 946 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 946 less than 100000):

1 × 946 = 946
2 × 946 = 1892
3 × 946 = 2838
...
104 × 946 = 98384
105 × 946 = 99330