What are the numbers divisible by 950?

950, 1900, 2850, 3800, 4750, 5700, 6650, 7600, 8550, 9500, 10450, 11400, 12350, 13300, 14250, 15200, 16150, 17100, 18050, 19000, 19950, 20900, 21850, 22800, 23750, 24700, 25650, 26600, 27550, 28500, 29450, 30400, 31350, 32300, 33250, 34200, 35150, 36100, 37050, 38000, 38950, 39900, 40850, 41800, 42750, 43700, 44650, 45600, 46550, 47500, 48450, 49400, 50350, 51300, 52250, 53200, 54150, 55100, 56050, 57000, 57950, 58900, 59850, 60800, 61750, 62700, 63650, 64600, 65550, 66500, 67450, 68400, 69350, 70300, 71250, 72200, 73150, 74100, 75050, 76000, 76950, 77900, 78850, 79800, 80750, 81700, 82650, 83600, 84550, 85500, 86450, 87400, 88350, 89300, 90250, 91200, 92150, 93100, 94050, 95000, 95950, 96900, 97850, 98800, 99750

There is a total of 105 numbers (up to 100000) that are divisible by 950.
The sum of these numbers is 5286750.
The arithmetic mean of these numbers is 50350.

How to find the numbers divisible by 950?

Finding all the numbers that can be divided by 950 is essentially the same as searching for the multiples of 950: if a number N is a multiple of 950, then 950 is a divisor of N.

Indeed, if we assume that N is a multiple of 950, this means there exists an integer k such that:

$k \times 950 = N$

Conversely, the result of N divided by 950 is this same integer k (without any remainder):

$k = \frac{N}{950}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 950 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 950 less than 100000):

1 × 950 = 950
2 × 950 = 1900
3 × 950 = 2850
...
104 × 950 = 98800
105 × 950 = 99750