What are the numbers divisible by 961?

961, 1922, 2883, 3844, 4805, 5766, 6727, 7688, 8649, 9610, 10571, 11532, 12493, 13454, 14415, 15376, 16337, 17298, 18259, 19220, 20181, 21142, 22103, 23064, 24025, 24986, 25947, 26908, 27869, 28830, 29791, 30752, 31713, 32674, 33635, 34596, 35557, 36518, 37479, 38440, 39401, 40362, 41323, 42284, 43245, 44206, 45167, 46128, 47089, 48050, 49011, 49972, 50933, 51894, 52855, 53816, 54777, 55738, 56699, 57660, 58621, 59582, 60543, 61504, 62465, 63426, 64387, 65348, 66309, 67270, 68231, 69192, 70153, 71114, 72075, 73036, 73997, 74958, 75919, 76880, 77841, 78802, 79763, 80724, 81685, 82646, 83607, 84568, 85529, 86490, 87451, 88412, 89373, 90334, 91295, 92256, 93217, 94178, 95139, 96100, 97061, 98022, 98983, 99944

There is a total of 104 numbers (up to 100000) that are divisible by 961.
The sum of these numbers is 5247060.
The arithmetic mean of these numbers is 50452.5.

How to find the numbers divisible by 961?

Finding all the numbers that can be divided by 961 is essentially the same as searching for the multiples of 961: if a number N is a multiple of 961, then 961 is a divisor of N.

Indeed, if we assume that N is a multiple of 961, this means there exists an integer k such that:

$k \times 961 = N$

Conversely, the result of N divided by 961 is this same integer k (without any remainder):

$k = \frac{N}{961}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 961 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 961 less than 100000):

1 × 961 = 961
2 × 961 = 1922
3 × 961 = 2883
...
103 × 961 = 98983
104 × 961 = 99944