What are the numbers divisible by 968?

968, 1936, 2904, 3872, 4840, 5808, 6776, 7744, 8712, 9680, 10648, 11616, 12584, 13552, 14520, 15488, 16456, 17424, 18392, 19360, 20328, 21296, 22264, 23232, 24200, 25168, 26136, 27104, 28072, 29040, 30008, 30976, 31944, 32912, 33880, 34848, 35816, 36784, 37752, 38720, 39688, 40656, 41624, 42592, 43560, 44528, 45496, 46464, 47432, 48400, 49368, 50336, 51304, 52272, 53240, 54208, 55176, 56144, 57112, 58080, 59048, 60016, 60984, 61952, 62920, 63888, 64856, 65824, 66792, 67760, 68728, 69696, 70664, 71632, 72600, 73568, 74536, 75504, 76472, 77440, 78408, 79376, 80344, 81312, 82280, 83248, 84216, 85184, 86152, 87120, 88088, 89056, 90024, 90992, 91960, 92928, 93896, 94864, 95832, 96800, 97768, 98736, 99704

There is a total of 103 numbers (up to 100000) that are divisible by 968.
The sum of these numbers is 5184608.
The arithmetic mean of these numbers is 50336.

How to find the numbers divisible by 968?

Finding all the numbers that can be divided by 968 is essentially the same as searching for the multiples of 968: if a number N is a multiple of 968, then 968 is a divisor of N.

Indeed, if we assume that N is a multiple of 968, this means there exists an integer k such that:

$k \times 968 = N$

Conversely, the result of N divided by 968 is this same integer k (without any remainder):

$k = \frac{N}{968}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 968 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 968 less than 100000):

1 × 968 = 968
2 × 968 = 1936
3 × 968 = 2904
...
102 × 968 = 98736
103 × 968 = 99704