What are the numbers divisible by 971?

971, 1942, 2913, 3884, 4855, 5826, 6797, 7768, 8739, 9710, 10681, 11652, 12623, 13594, 14565, 15536, 16507, 17478, 18449, 19420, 20391, 21362, 22333, 23304, 24275, 25246, 26217, 27188, 28159, 29130, 30101, 31072, 32043, 33014, 33985, 34956, 35927, 36898, 37869, 38840, 39811, 40782, 41753, 42724, 43695, 44666, 45637, 46608, 47579, 48550, 49521, 50492, 51463, 52434, 53405, 54376, 55347, 56318, 57289, 58260, 59231, 60202, 61173, 62144, 63115, 64086, 65057, 66028, 66999, 67970, 68941, 69912, 70883, 71854, 72825, 73796, 74767, 75738, 76709, 77680, 78651, 79622, 80593, 81564, 82535, 83506, 84477, 85448, 86419, 87390, 88361, 89332, 90303, 91274, 92245, 93216, 94187, 95158, 96129, 97100, 98071, 99042

There is a total of 102 numbers (up to 100000) that are divisible by 971.
The sum of these numbers is 5100663.
The arithmetic mean of these numbers is 50006.5.

How to find the numbers divisible by 971?

Finding all the numbers that can be divided by 971 is essentially the same as searching for the multiples of 971: if a number N is a multiple of 971, then 971 is a divisor of N.

Indeed, if we assume that N is a multiple of 971, this means there exists an integer k such that:

$k \times 971 = N$

Conversely, the result of N divided by 971 is this same integer k (without any remainder):

$k = \frac{N}{971}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 971 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 971 less than 100000):

1 × 971 = 971
2 × 971 = 1942
3 × 971 = 2913
...
101 × 971 = 98071
102 × 971 = 99042