What are the numbers divisible by 980?

980, 1960, 2940, 3920, 4900, 5880, 6860, 7840, 8820, 9800, 10780, 11760, 12740, 13720, 14700, 15680, 16660, 17640, 18620, 19600, 20580, 21560, 22540, 23520, 24500, 25480, 26460, 27440, 28420, 29400, 30380, 31360, 32340, 33320, 34300, 35280, 36260, 37240, 38220, 39200, 40180, 41160, 42140, 43120, 44100, 45080, 46060, 47040, 48020, 49000, 49980, 50960, 51940, 52920, 53900, 54880, 55860, 56840, 57820, 58800, 59780, 60760, 61740, 62720, 63700, 64680, 65660, 66640, 67620, 68600, 69580, 70560, 71540, 72520, 73500, 74480, 75460, 76440, 77420, 78400, 79380, 80360, 81340, 82320, 83300, 84280, 85260, 86240, 87220, 88200, 89180, 90160, 91140, 92120, 93100, 94080, 95060, 96040, 97020, 98000, 98980, 99960

There is a total of 102 numbers (up to 100000) that are divisible by 980.
The sum of these numbers is 5147940.
The arithmetic mean of these numbers is 50470.

How to find the numbers divisible by 980?

Finding all the numbers that can be divided by 980 is essentially the same as searching for the multiples of 980: if a number N is a multiple of 980, then 980 is a divisor of N.

Indeed, if we assume that N is a multiple of 980, this means there exists an integer k such that:

$k \times 980 = N$

Conversely, the result of N divided by 980 is this same integer k (without any remainder):

$k = \frac{N}{980}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 980 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 980 less than 100000):

1 × 980 = 980
2 × 980 = 1960
3 × 980 = 2940
...
101 × 980 = 98980
102 × 980 = 99960