What are the numbers divisible by 983?

983, 1966, 2949, 3932, 4915, 5898, 6881, 7864, 8847, 9830, 10813, 11796, 12779, 13762, 14745, 15728, 16711, 17694, 18677, 19660, 20643, 21626, 22609, 23592, 24575, 25558, 26541, 27524, 28507, 29490, 30473, 31456, 32439, 33422, 34405, 35388, 36371, 37354, 38337, 39320, 40303, 41286, 42269, 43252, 44235, 45218, 46201, 47184, 48167, 49150, 50133, 51116, 52099, 53082, 54065, 55048, 56031, 57014, 57997, 58980, 59963, 60946, 61929, 62912, 63895, 64878, 65861, 66844, 67827, 68810, 69793, 70776, 71759, 72742, 73725, 74708, 75691, 76674, 77657, 78640, 79623, 80606, 81589, 82572, 83555, 84538, 85521, 86504, 87487, 88470, 89453, 90436, 91419, 92402, 93385, 94368, 95351, 96334, 97317, 98300, 99283

There is a total of 101 numbers (up to 100000) that are divisible by 983.
The sum of these numbers is 5063433.
The arithmetic mean of these numbers is 50133.

How to find the numbers divisible by 983?

Finding all the numbers that can be divided by 983 is essentially the same as searching for the multiples of 983: if a number N is a multiple of 983, then 983 is a divisor of N.

Indeed, if we assume that N is a multiple of 983, this means there exists an integer k such that:

$k \times 983 = N$

Conversely, the result of N divided by 983 is this same integer k (without any remainder):

$k = \frac{N}{983}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 983 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 983 less than 100000):

1 × 983 = 983
2 × 983 = 1966
3 × 983 = 2949
...
100 × 983 = 98300
101 × 983 = 99283