What are the numbers divisible by 985?

985, 1970, 2955, 3940, 4925, 5910, 6895, 7880, 8865, 9850, 10835, 11820, 12805, 13790, 14775, 15760, 16745, 17730, 18715, 19700, 20685, 21670, 22655, 23640, 24625, 25610, 26595, 27580, 28565, 29550, 30535, 31520, 32505, 33490, 34475, 35460, 36445, 37430, 38415, 39400, 40385, 41370, 42355, 43340, 44325, 45310, 46295, 47280, 48265, 49250, 50235, 51220, 52205, 53190, 54175, 55160, 56145, 57130, 58115, 59100, 60085, 61070, 62055, 63040, 64025, 65010, 65995, 66980, 67965, 68950, 69935, 70920, 71905, 72890, 73875, 74860, 75845, 76830, 77815, 78800, 79785, 80770, 81755, 82740, 83725, 84710, 85695, 86680, 87665, 88650, 89635, 90620, 91605, 92590, 93575, 94560, 95545, 96530, 97515, 98500, 99485

There is a total of 101 numbers (up to 100000) that are divisible by 985.
The sum of these numbers is 5073735.
The arithmetic mean of these numbers is 50235.

How to find the numbers divisible by 985?

Finding all the numbers that can be divided by 985 is essentially the same as searching for the multiples of 985: if a number N is a multiple of 985, then 985 is a divisor of N.

Indeed, if we assume that N is a multiple of 985, this means there exists an integer k such that:

$k \times 985 = N$

Conversely, the result of N divided by 985 is this same integer k (without any remainder):

$k = \frac{N}{985}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 985 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 985 less than 100000):

1 × 985 = 985
2 × 985 = 1970
3 × 985 = 2955
...
100 × 985 = 98500
101 × 985 = 99485