What are the numbers divisible by 987?

987, 1974, 2961, 3948, 4935, 5922, 6909, 7896, 8883, 9870, 10857, 11844, 12831, 13818, 14805, 15792, 16779, 17766, 18753, 19740, 20727, 21714, 22701, 23688, 24675, 25662, 26649, 27636, 28623, 29610, 30597, 31584, 32571, 33558, 34545, 35532, 36519, 37506, 38493, 39480, 40467, 41454, 42441, 43428, 44415, 45402, 46389, 47376, 48363, 49350, 50337, 51324, 52311, 53298, 54285, 55272, 56259, 57246, 58233, 59220, 60207, 61194, 62181, 63168, 64155, 65142, 66129, 67116, 68103, 69090, 70077, 71064, 72051, 73038, 74025, 75012, 75999, 76986, 77973, 78960, 79947, 80934, 81921, 82908, 83895, 84882, 85869, 86856, 87843, 88830, 89817, 90804, 91791, 92778, 93765, 94752, 95739, 96726, 97713, 98700, 99687

There is a total of 101 numbers (up to 100000) that are divisible by 987.
The sum of these numbers is 5084037.
The arithmetic mean of these numbers is 50337.

How to find the numbers divisible by 987?

Finding all the numbers that can be divided by 987 is essentially the same as searching for the multiples of 987: if a number N is a multiple of 987, then 987 is a divisor of N.

Indeed, if we assume that N is a multiple of 987, this means there exists an integer k such that:

$k \times 987 = N$

Conversely, the result of N divided by 987 is this same integer k (without any remainder):

$k = \frac{N}{987}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 987 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 987 less than 100000):

1 × 987 = 987
2 × 987 = 1974
3 × 987 = 2961
...
100 × 987 = 98700
101 × 987 = 99687