What are the numbers divisible by 989?
989, 1978, 2967, 3956, 4945, 5934, 6923, 7912, 8901, 9890, 10879, 11868, 12857, 13846, 14835, 15824, 16813, 17802, 18791, 19780, 20769, 21758, 22747, 23736, 24725, 25714, 26703, 27692, 28681, 29670, 30659, 31648, 32637, 33626, 34615, 35604, 36593, 37582, 38571, 39560, 40549, 41538, 42527, 43516, 44505, 45494, 46483, 47472, 48461, 49450, 50439, 51428, 52417, 53406, 54395, 55384, 56373, 57362, 58351, 59340, 60329, 61318, 62307, 63296, 64285, 65274, 66263, 67252, 68241, 69230, 70219, 71208, 72197, 73186, 74175, 75164, 76153, 77142, 78131, 79120, 80109, 81098, 82087, 83076, 84065, 85054, 86043, 87032, 88021, 89010, 89999, 90988, 91977, 92966, 93955, 94944, 95933, 96922, 97911, 98900, 99889
- There is a total of 101 numbers (up to 100000) that are divisible by 989.
- The sum of these numbers is 5094339.
- The arithmetic mean of these numbers is 50439.
How to find the numbers divisible by 989?
Finding all the numbers that can be divided by 989 is essentially the same as searching for the multiples of 989: if a number N is a multiple of 989, then 989 is a divisor of N.
Indeed, if we assume that N is a multiple of 989, this means there exists an integer k such that:
Conversely, the result of N divided by 989 is this same integer k (without any remainder):
From this we can see that, theoretically, there's an infinite quantity of multiples of 989 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).
However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 989 less than 100000):
- 1 × 989 = 989
- 2 × 989 = 1978
- 3 × 989 = 2967
- ...
- 100 × 989 = 98900
- 101 × 989 = 99889