What are the numbers divisible by 992?

992, 1984, 2976, 3968, 4960, 5952, 6944, 7936, 8928, 9920, 10912, 11904, 12896, 13888, 14880, 15872, 16864, 17856, 18848, 19840, 20832, 21824, 22816, 23808, 24800, 25792, 26784, 27776, 28768, 29760, 30752, 31744, 32736, 33728, 34720, 35712, 36704, 37696, 38688, 39680, 40672, 41664, 42656, 43648, 44640, 45632, 46624, 47616, 48608, 49600, 50592, 51584, 52576, 53568, 54560, 55552, 56544, 57536, 58528, 59520, 60512, 61504, 62496, 63488, 64480, 65472, 66464, 67456, 68448, 69440, 70432, 71424, 72416, 73408, 74400, 75392, 76384, 77376, 78368, 79360, 80352, 81344, 82336, 83328, 84320, 85312, 86304, 87296, 88288, 89280, 90272, 91264, 92256, 93248, 94240, 95232, 96224, 97216, 98208, 99200

There is a total of 100 numbers (up to 100000) that are divisible by 992.
The sum of these numbers is 5009600.
The arithmetic mean of these numbers is 50096.

How to find the numbers divisible by 992?

Finding all the numbers that can be divided by 992 is essentially the same as searching for the multiples of 992: if a number N is a multiple of 992, then 992 is a divisor of N.

Indeed, if we assume that N is a multiple of 992, this means there exists an integer k such that:

$k \times 992 = N$

Conversely, the result of N divided by 992 is this same integer k (without any remainder):

$k = \frac{N}{992}$

From this we can see that, theoretically, there's an infinite quantity of multiples of 992 (we can keep multiplying it by increasingly larger integers, without ever reaching the end).

However, in this instance, we've chosen to set an arbitrary limit (specifically, the multiples of 992 less than 100000):

1 × 992 = 992
2 × 992 = 1984
3 × 992 = 2976
...
99 × 992 = 98208
100 × 992 = 99200