What are the divisors of 1229?

1, 1229

2 odd divisors

1, 1229

How to compute the divisors of 1229?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

N mod M = 0

Brute force algorithm

We could start by using a brute-force method which would involve dividing 1229 by each of the numbers from 1 to 1229 to determine which ones have a remainder equal to 0.

Remainder = N ( M × N M )

(where N M is the integer part of the quotient)

  • 1229 / 1 = 1229 (the remainder is 0, so 1 is a divisor of 1229)
  • 1229 / 2 = 614.5 (the remainder is 1, so 2 is not a divisor of 1229)
  • 1229 / 3 = 409.66666666667 (the remainder is 2, so 3 is not a divisor of 1229)
  • ...
  • 1229 / 1228 = 1.0008143322476 (the remainder is 1, so 1228 is not a divisor of 1229)
  • 1229 / 1229 = 1 (the remainder is 0, so 1229 is a divisor of 1229)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 1229 (i.e. 35.057096285916). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

D × d = N

(thus, if N D = d , then N d = D )

  • 1229 / 1 = 1229 (the remainder is 0, so 1 and 1229 are divisors of 1229)
  • 1229 / 2 = 614.5 (the remainder is 1, so 2 is not a divisor of 1229)
  • 1229 / 3 = 409.66666666667 (the remainder is 2, so 3 is not a divisor of 1229)
  • ...
  • 1229 / 34 = 36.147058823529 (the remainder is 5, so 34 is not a divisor of 1229)
  • 1229 / 35 = 35.114285714286 (the remainder is 4, so 35 is not a divisor of 1229)