What are the divisors of 1433?

1, 1433

2 odd divisors

1, 1433

How to compute the divisors of 1433?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

N mod M = 0

Brute force algorithm

We could start by using a brute-force method which would involve dividing 1433 by each of the numbers from 1 to 1433 to determine which ones have a remainder equal to 0.

Remainder = N ( M × N M )

(where N M is the integer part of the quotient)

  • 1433 / 1 = 1433 (the remainder is 0, so 1 is a divisor of 1433)
  • 1433 / 2 = 716.5 (the remainder is 1, so 2 is not a divisor of 1433)
  • 1433 / 3 = 477.66666666667 (the remainder is 2, so 3 is not a divisor of 1433)
  • ...
  • 1433 / 1432 = 1.0006983240223 (the remainder is 1, so 1432 is not a divisor of 1433)
  • 1433 / 1433 = 1 (the remainder is 0, so 1433 is a divisor of 1433)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 1433 (i.e. 37.854986461495). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

D × d = N

(thus, if N D = d , then N d = D )

  • 1433 / 1 = 1433 (the remainder is 0, so 1 and 1433 are divisors of 1433)
  • 1433 / 2 = 716.5 (the remainder is 1, so 2 is not a divisor of 1433)
  • 1433 / 3 = 477.66666666667 (the remainder is 2, so 3 is not a divisor of 1433)
  • ...
  • 1433 / 36 = 39.805555555556 (the remainder is 29, so 36 is not a divisor of 1433)
  • 1433 / 37 = 38.72972972973 (the remainder is 27, so 37 is not a divisor of 1433)