What are the divisors of 1739?

1, 37, 47, 1739

There is a total of 4 positive divisors.
The sum of these divisors is 1824.
The arithmetic mean is 456.

4 odd divisors

1, 37, 47, 1739

How to compute the divisors of 1739?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 1739 by each of the numbers from 1 to 1739 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

1739 / 1 = 1739 (the remainder is 0, so 1 is a divisor of 1739)
1739 / 2 = 869.5 (the remainder is 1, so 2 is not a divisor of 1739)
1739 / 3 = 579.66666666667 (the remainder is 2, so 3 is not a divisor of 1739)
...
1739 / 1738 = 1.0005753739931 (the remainder is 1, so 1738 is not a divisor of 1739)
1739 / 1739 = 1 (the remainder is 0, so 1739 is a divisor of 1739)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 1739 (i.e. 41.701318923986). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

1739 / 1 = 1739 (the remainder is 0, so 1 and 1739 are divisors of 1739)
1739 / 2 = 869.5 (the remainder is 1, so 2 is not a divisor of 1739)
1739 / 3 = 579.66666666667 (the remainder is 2, so 3 is not a divisor of 1739)
...
1739 / 40 = 43.475 (the remainder is 19, so 40 is not a divisor of 1739)
1739 / 41 = 42.414634146341 (the remainder is 17, so 41 is not a divisor of 1739)