What are the divisors of 1751?

1, 17, 103, 1751

There is a total of 4 positive divisors.
The sum of these divisors is 1872.
The arithmetic mean is 468.

4 odd divisors

1, 17, 103, 1751

How to compute the divisors of 1751?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 1751 by each of the numbers from 1 to 1751 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

1751 / 1 = 1751 (the remainder is 0, so 1 is a divisor of 1751)
1751 / 2 = 875.5 (the remainder is 1, so 2 is not a divisor of 1751)
1751 / 3 = 583.66666666667 (the remainder is 2, so 3 is not a divisor of 1751)
...
1751 / 1750 = 1.0005714285714 (the remainder is 1, so 1750 is not a divisor of 1751)
1751 / 1751 = 1 (the remainder is 0, so 1751 is a divisor of 1751)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 1751 (i.e. 41.844951905815). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

1751 / 1 = 1751 (the remainder is 0, so 1 and 1751 are divisors of 1751)
1751 / 2 = 875.5 (the remainder is 1, so 2 is not a divisor of 1751)
1751 / 3 = 583.66666666667 (the remainder is 2, so 3 is not a divisor of 1751)
...
1751 / 40 = 43.775 (the remainder is 31, so 40 is not a divisor of 1751)
1751 / 41 = 42.707317073171 (the remainder is 29, so 41 is not a divisor of 1751)