What are the divisors of 1753?

1, 1753

There is a total of 2 positive divisors.
The sum of these divisors is 1754.
The arithmetic mean is 877.

2 odd divisors

1, 1753

How to compute the divisors of 1753?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 1753 by each of the numbers from 1 to 1753 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

1753 / 1 = 1753 (the remainder is 0, so 1 is a divisor of 1753)
1753 / 2 = 876.5 (the remainder is 1, so 2 is not a divisor of 1753)
1753 / 3 = 584.33333333333 (the remainder is 1, so 3 is not a divisor of 1753)
...
1753 / 1752 = 1.0005707762557 (the remainder is 1, so 1752 is not a divisor of 1753)
1753 / 1753 = 1 (the remainder is 0, so 1753 is a divisor of 1753)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 1753 (i.e. 41.868842830917). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

1753 / 1 = 1753 (the remainder is 0, so 1 and 1753 are divisors of 1753)
1753 / 2 = 876.5 (the remainder is 1, so 2 is not a divisor of 1753)
1753 / 3 = 584.33333333333 (the remainder is 1, so 3 is not a divisor of 1753)
...
1753 / 40 = 43.825 (the remainder is 33, so 40 is not a divisor of 1753)
1753 / 41 = 42.756097560976 (the remainder is 31, so 41 is not a divisor of 1753)