What are the divisors of 1883?

1, 7, 269, 1883

There is a total of 4 positive divisors.
The sum of these divisors is 2160.
The arithmetic mean is 540.

4 odd divisors

1, 7, 269, 1883

How to compute the divisors of 1883?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 1883 by each of the numbers from 1 to 1883 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

1883 / 1 = 1883 (the remainder is 0, so 1 is a divisor of 1883)
1883 / 2 = 941.5 (the remainder is 1, so 2 is not a divisor of 1883)
1883 / 3 = 627.66666666667 (the remainder is 2, so 3 is not a divisor of 1883)
...
1883 / 1882 = 1.0005313496281 (the remainder is 1, so 1882 is not a divisor of 1883)
1883 / 1883 = 1 (the remainder is 0, so 1883 is a divisor of 1883)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 1883 (i.e. 43.393547907494). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

1883 / 1 = 1883 (the remainder is 0, so 1 and 1883 are divisors of 1883)
1883 / 2 = 941.5 (the remainder is 1, so 2 is not a divisor of 1883)
1883 / 3 = 627.66666666667 (the remainder is 2, so 3 is not a divisor of 1883)
...
1883 / 42 = 44.833333333333 (the remainder is 35, so 42 is not a divisor of 1883)
1883 / 43 = 43.790697674419 (the remainder is 34, so 43 is not a divisor of 1883)