What are the divisors of 2407?

1, 29, 83, 2407

There is a total of 4 positive divisors.
The sum of these divisors is 2520.
The arithmetic mean is 630.

4 odd divisors

1, 29, 83, 2407

How to compute the divisors of 2407?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 2407 by each of the numbers from 1 to 2407 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

2407 / 1 = 2407 (the remainder is 0, so 1 is a divisor of 2407)
2407 / 2 = 1203.5 (the remainder is 1, so 2 is not a divisor of 2407)
2407 / 3 = 802.33333333333 (the remainder is 1, so 3 is not a divisor of 2407)
...
2407 / 2406 = 1.0004156275977 (the remainder is 1, so 2406 is not a divisor of 2407)
2407 / 2407 = 1 (the remainder is 0, so 2407 is a divisor of 2407)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 2407 (i.e. 49.061186288144). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

2407 / 1 = 2407 (the remainder is 0, so 1 and 2407 are divisors of 2407)
2407 / 2 = 1203.5 (the remainder is 1, so 2 is not a divisor of 2407)
2407 / 3 = 802.33333333333 (the remainder is 1, so 3 is not a divisor of 2407)
...
2407 / 48 = 50.145833333333 (the remainder is 7, so 48 is not a divisor of 2407)
2407 / 49 = 49.122448979592 (the remainder is 6, so 49 is not a divisor of 2407)