What are the divisors of 2783?

1, 11, 23, 121, 253, 2783

There is a total of 6 positive divisors.
The sum of these divisors is 3192.
The arithmetic mean is 532.

6 odd divisors

1, 11, 23, 121, 253, 2783

How to compute the divisors of 2783?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 2783 by each of the numbers from 1 to 2783 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

2783 / 1 = 2783 (the remainder is 0, so 1 is a divisor of 2783)
2783 / 2 = 1391.5 (the remainder is 1, so 2 is not a divisor of 2783)
2783 / 3 = 927.66666666667 (the remainder is 2, so 3 is not a divisor of 2783)
...
2783 / 2782 = 1.0003594536305 (the remainder is 1, so 2782 is not a divisor of 2783)
2783 / 2783 = 1 (the remainder is 0, so 2783 is a divisor of 2783)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 2783 (i.e. 52.75414675644). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

2783 / 1 = 2783 (the remainder is 0, so 1 and 2783 are divisors of 2783)
2783 / 2 = 1391.5 (the remainder is 1, so 2 is not a divisor of 2783)
2783 / 3 = 927.66666666667 (the remainder is 2, so 3 is not a divisor of 2783)
...
2783 / 51 = 54.56862745098 (the remainder is 29, so 51 is not a divisor of 2783)
2783 / 52 = 53.519230769231 (the remainder is 27, so 52 is not a divisor of 2783)