What are the divisors of 2845?

1, 5, 569, 2845

There is a total of 4 positive divisors.
The sum of these divisors is 3420.
The arithmetic mean is 855.

4 odd divisors

1, 5, 569, 2845

How to compute the divisors of 2845?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 2845 by each of the numbers from 1 to 2845 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

2845 / 1 = 2845 (the remainder is 0, so 1 is a divisor of 2845)
2845 / 2 = 1422.5 (the remainder is 1, so 2 is not a divisor of 2845)
2845 / 3 = 948.33333333333 (the remainder is 1, so 3 is not a divisor of 2845)
...
2845 / 2844 = 1.0003516174402 (the remainder is 1, so 2844 is not a divisor of 2845)
2845 / 2845 = 1 (the remainder is 0, so 2845 is a divisor of 2845)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 2845 (i.e. 53.338541412378). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

2845 / 1 = 2845 (the remainder is 0, so 1 and 2845 are divisors of 2845)
2845 / 2 = 1422.5 (the remainder is 1, so 2 is not a divisor of 2845)
2845 / 3 = 948.33333333333 (the remainder is 1, so 3 is not a divisor of 2845)
...
2845 / 52 = 54.711538461538 (the remainder is 37, so 52 is not a divisor of 2845)
2845 / 53 = 53.679245283019 (the remainder is 36, so 53 is not a divisor of 2845)