What are the divisors of 2971?

1, 2971

2 odd divisors

1, 2971

How to compute the divisors of 2971?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

N mod M = 0

Brute force algorithm

We could start by using a brute-force method which would involve dividing 2971 by each of the numbers from 1 to 2971 to determine which ones have a remainder equal to 0.

Remainder = N ( M × N M )

(where N M is the integer part of the quotient)

  • 2971 / 1 = 2971 (the remainder is 0, so 1 is a divisor of 2971)
  • 2971 / 2 = 1485.5 (the remainder is 1, so 2 is not a divisor of 2971)
  • 2971 / 3 = 990.33333333333 (the remainder is 1, so 3 is not a divisor of 2971)
  • ...
  • 2971 / 2970 = 1.0003367003367 (the remainder is 1, so 2970 is not a divisor of 2971)
  • 2971 / 2971 = 1 (the remainder is 0, so 2971 is a divisor of 2971)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 2971 (i.e. 54.506880299647). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

D × d = N

(thus, if N D = d , then N d = D )

  • 2971 / 1 = 2971 (the remainder is 0, so 1 and 2971 are divisors of 2971)
  • 2971 / 2 = 1485.5 (the remainder is 1, so 2 is not a divisor of 2971)
  • 2971 / 3 = 990.33333333333 (the remainder is 1, so 3 is not a divisor of 2971)
  • ...
  • 2971 / 53 = 56.056603773585 (the remainder is 3, so 53 is not a divisor of 2971)
  • 2971 / 54 = 55.018518518519 (the remainder is 1, so 54 is not a divisor of 2971)