What are the divisors of 3007?

1, 31, 97, 3007

4 odd divisors

1, 31, 97, 3007

How to compute the divisors of 3007?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

N mod M = 0

Brute force algorithm

We could start by using a brute-force method which would involve dividing 3007 by each of the numbers from 1 to 3007 to determine which ones have a remainder equal to 0.

Remainder = N ( M × N M )

(where N M is the integer part of the quotient)

  • 3007 / 1 = 3007 (the remainder is 0, so 1 is a divisor of 3007)
  • 3007 / 2 = 1503.5 (the remainder is 1, so 2 is not a divisor of 3007)
  • 3007 / 3 = 1002.3333333333 (the remainder is 1, so 3 is not a divisor of 3007)
  • ...
  • 3007 / 3006 = 1.0003326679973 (the remainder is 1, so 3006 is not a divisor of 3007)
  • 3007 / 3007 = 1 (the remainder is 0, so 3007 is a divisor of 3007)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 3007 (i.e. 54.836119483421). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

D × d = N

(thus, if N D = d , then N d = D )

  • 3007 / 1 = 3007 (the remainder is 0, so 1 and 3007 are divisors of 3007)
  • 3007 / 2 = 1503.5 (the remainder is 1, so 2 is not a divisor of 3007)
  • 3007 / 3 = 1002.3333333333 (the remainder is 1, so 3 is not a divisor of 3007)
  • ...
  • 3007 / 53 = 56.735849056604 (the remainder is 39, so 53 is not a divisor of 3007)
  • 3007 / 54 = 55.685185185185 (the remainder is 37, so 54 is not a divisor of 3007)