What are the divisors of 3023?

1, 3023

There is a total of 2 positive divisors.
The sum of these divisors is 3024.
The arithmetic mean is 1512.

2 odd divisors

1, 3023

How to compute the divisors of 3023?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 3023 by each of the numbers from 1 to 3023 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

3023 / 1 = 3023 (the remainder is 0, so 1 is a divisor of 3023)
3023 / 2 = 1511.5 (the remainder is 1, so 2 is not a divisor of 3023)
3023 / 3 = 1007.6666666667 (the remainder is 2, so 3 is not a divisor of 3023)
...
3023 / 3022 = 1.0003309066843 (the remainder is 1, so 3022 is not a divisor of 3023)
3023 / 3023 = 1 (the remainder is 0, so 3023 is a divisor of 3023)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 3023 (i.e. 54.981815175565). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

3023 / 1 = 3023 (the remainder is 0, so 1 and 3023 are divisors of 3023)
3023 / 2 = 1511.5 (the remainder is 1, so 2 is not a divisor of 3023)
3023 / 3 = 1007.6666666667 (the remainder is 2, so 3 is not a divisor of 3023)
...
3023 / 53 = 57.037735849057 (the remainder is 2, so 53 is not a divisor of 3023)
3023 / 54 = 55.981481481481 (the remainder is 53, so 54 is not a divisor of 3023)