What are the divisors of 3037?

1, 3037

2 odd divisors

1, 3037

How to compute the divisors of 3037?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

N mod M = 0

Brute force algorithm

We could start by using a brute-force method which would involve dividing 3037 by each of the numbers from 1 to 3037 to determine which ones have a remainder equal to 0.

Remainder = N ( M × N M )

(where N M is the integer part of the quotient)

  • 3037 / 1 = 3037 (the remainder is 0, so 1 is a divisor of 3037)
  • 3037 / 2 = 1518.5 (the remainder is 1, so 2 is not a divisor of 3037)
  • 3037 / 3 = 1012.3333333333 (the remainder is 1, so 3 is not a divisor of 3037)
  • ...
  • 3037 / 3036 = 1.0003293807642 (the remainder is 1, so 3036 is not a divisor of 3037)
  • 3037 / 3037 = 1 (the remainder is 0, so 3037 is a divisor of 3037)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 3037 (i.e. 55.108982933819). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

D × d = N

(thus, if N D = d , then N d = D )

  • 3037 / 1 = 3037 (the remainder is 0, so 1 and 3037 are divisors of 3037)
  • 3037 / 2 = 1518.5 (the remainder is 1, so 2 is not a divisor of 3037)
  • 3037 / 3 = 1012.3333333333 (the remainder is 1, so 3 is not a divisor of 3037)
  • ...
  • 3037 / 54 = 56.240740740741 (the remainder is 13, so 54 is not a divisor of 3037)
  • 3037 / 55 = 55.218181818182 (the remainder is 12, so 55 is not a divisor of 3037)