What are the divisors of 3125?

1, 5, 25, 125, 625, 3125

There is a total of 6 positive divisors.
The sum of these divisors is 3906.
The arithmetic mean is 651.

6 odd divisors

1, 5, 25, 125, 625, 3125

How to compute the divisors of 3125?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 3125 by each of the numbers from 1 to 3125 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

3125 / 1 = 3125 (the remainder is 0, so 1 is a divisor of 3125)
3125 / 2 = 1562.5 (the remainder is 1, so 2 is not a divisor of 3125)
3125 / 3 = 1041.6666666667 (the remainder is 2, so 3 is not a divisor of 3125)
...
3125 / 3124 = 1.0003201024328 (the remainder is 1, so 3124 is not a divisor of 3125)
3125 / 3125 = 1 (the remainder is 0, so 3125 is a divisor of 3125)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 3125 (i.e. 55.901699437495). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

3125 / 1 = 3125 (the remainder is 0, so 1 and 3125 are divisors of 3125)
3125 / 2 = 1562.5 (the remainder is 1, so 2 is not a divisor of 3125)
3125 / 3 = 1041.6666666667 (the remainder is 2, so 3 is not a divisor of 3125)
...
3125 / 54 = 57.87037037037 (the remainder is 47, so 54 is not a divisor of 3125)
3125 / 55 = 56.818181818182 (the remainder is 45, so 55 is not a divisor of 3125)