What are the divisors of 3145?

1, 5, 17, 37, 85, 185, 629, 3145

There is a total of 8 positive divisors.
The sum of these divisors is 4104.
The arithmetic mean is 513.

8 odd divisors

1, 5, 17, 37, 85, 185, 629, 3145

How to compute the divisors of 3145?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 3145 by each of the numbers from 1 to 3145 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

3145 / 1 = 3145 (the remainder is 0, so 1 is a divisor of 3145)
3145 / 2 = 1572.5 (the remainder is 1, so 2 is not a divisor of 3145)
3145 / 3 = 1048.3333333333 (the remainder is 1, so 3 is not a divisor of 3145)
...
3145 / 3144 = 1.0003180661578 (the remainder is 1, so 3144 is not a divisor of 3145)
3145 / 3145 = 1 (the remainder is 0, so 3145 is a divisor of 3145)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 3145 (i.e. 56.08029957124). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

3145 / 1 = 3145 (the remainder is 0, so 1 and 3145 are divisors of 3145)
3145 / 2 = 1572.5 (the remainder is 1, so 2 is not a divisor of 3145)
3145 / 3 = 1048.3333333333 (the remainder is 1, so 3 is not a divisor of 3145)
...
3145 / 55 = 57.181818181818 (the remainder is 10, so 55 is not a divisor of 3145)
3145 / 56 = 56.160714285714 (the remainder is 9, so 56 is not a divisor of 3145)