What are the divisors of 3329?

1, 3329

2 odd divisors

1, 3329

How to compute the divisors of 3329?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

N mod M = 0

Brute force algorithm

We could start by using a brute-force method which would involve dividing 3329 by each of the numbers from 1 to 3329 to determine which ones have a remainder equal to 0.

Remainder = N ( M × N M )

(where N M is the integer part of the quotient)

  • 3329 / 1 = 3329 (the remainder is 0, so 1 is a divisor of 3329)
  • 3329 / 2 = 1664.5 (the remainder is 1, so 2 is not a divisor of 3329)
  • 3329 / 3 = 1109.6666666667 (the remainder is 2, so 3 is not a divisor of 3329)
  • ...
  • 3329 / 3328 = 1.0003004807692 (the remainder is 1, so 3328 is not a divisor of 3329)
  • 3329 / 3329 = 1 (the remainder is 0, so 3329 is a divisor of 3329)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 3329 (i.e. 57.697486947007). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

D × d = N

(thus, if N D = d , then N d = D )

  • 3329 / 1 = 3329 (the remainder is 0, so 1 and 3329 are divisors of 3329)
  • 3329 / 2 = 1664.5 (the remainder is 1, so 2 is not a divisor of 3329)
  • 3329 / 3 = 1109.6666666667 (the remainder is 2, so 3 is not a divisor of 3329)
  • ...
  • 3329 / 56 = 59.446428571429 (the remainder is 25, so 56 is not a divisor of 3329)
  • 3329 / 57 = 58.40350877193 (the remainder is 23, so 57 is not a divisor of 3329)