What are the divisors of 347?

1, 347

2 odd divisors

1, 347

How to compute the divisors of 347?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

N mod M = 0

Brute force algorithm

We could start by using a brute-force method which would involve dividing 347 by each of the numbers from 1 to 347 to determine which ones have a remainder equal to 0.

Remainder = N ( M × N M )

(where N M is the integer part of the quotient)

  • 347 / 1 = 347 (the remainder is 0, so 1 is a divisor of 347)
  • 347 / 2 = 173.5 (the remainder is 1, so 2 is not a divisor of 347)
  • 347 / 3 = 115.66666666667 (the remainder is 2, so 3 is not a divisor of 347)
  • ...
  • 347 / 346 = 1.0028901734104 (the remainder is 1, so 346 is not a divisor of 347)
  • 347 / 347 = 1 (the remainder is 0, so 347 is a divisor of 347)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 347 (i.e. 18.627936010197). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

D × d = N

(thus, if N D = d , then N d = D )

  • 347 / 1 = 347 (the remainder is 0, so 1 and 347 are divisors of 347)
  • 347 / 2 = 173.5 (the remainder is 1, so 2 is not a divisor of 347)
  • 347 / 3 = 115.66666666667 (the remainder is 2, so 3 is not a divisor of 347)
  • ...
  • 347 / 17 = 20.411764705882 (the remainder is 7, so 17 is not a divisor of 347)
  • 347 / 18 = 19.277777777778 (the remainder is 5, so 18 is not a divisor of 347)