What are the divisors of 3475?

1, 5, 25, 139, 695, 3475

There is a total of 6 positive divisors.
The sum of these divisors is 4340.
The arithmetic mean is 723.33333333333.

6 odd divisors

1, 5, 25, 139, 695, 3475

How to compute the divisors of 3475?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 3475 by each of the numbers from 1 to 3475 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

3475 / 1 = 3475 (the remainder is 0, so 1 is a divisor of 3475)
3475 / 2 = 1737.5 (the remainder is 1, so 2 is not a divisor of 3475)
3475 / 3 = 1158.3333333333 (the remainder is 1, so 3 is not a divisor of 3475)
...
3475 / 3474 = 1.0002878526195 (the remainder is 1, so 3474 is not a divisor of 3475)
3475 / 3475 = 1 (the remainder is 0, so 3475 is a divisor of 3475)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 3475 (i.e. 58.949130612758). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

3475 / 1 = 3475 (the remainder is 0, so 1 and 3475 are divisors of 3475)
3475 / 2 = 1737.5 (the remainder is 1, so 2 is not a divisor of 3475)
3475 / 3 = 1158.3333333333 (the remainder is 1, so 3 is not a divisor of 3475)
...
3475 / 57 = 60.964912280702 (the remainder is 55, so 57 is not a divisor of 3475)
3475 / 58 = 59.913793103448 (the remainder is 53, so 58 is not a divisor of 3475)