What are the divisors of 3509?

1, 11, 29, 121, 319, 3509

There is a total of 6 positive divisors.
The sum of these divisors is 3990.
The arithmetic mean is 665.

6 odd divisors

1, 11, 29, 121, 319, 3509

How to compute the divisors of 3509?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 3509 by each of the numbers from 1 to 3509 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

3509 / 1 = 3509 (the remainder is 0, so 1 is a divisor of 3509)
3509 / 2 = 1754.5 (the remainder is 1, so 2 is not a divisor of 3509)
3509 / 3 = 1169.6666666667 (the remainder is 2, so 3 is not a divisor of 3509)
...
3509 / 3508 = 1.0002850627138 (the remainder is 1, so 3508 is not a divisor of 3509)
3509 / 3509 = 1 (the remainder is 0, so 3509 is a divisor of 3509)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 3509 (i.e. 59.23681287848). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

3509 / 1 = 3509 (the remainder is 0, so 1 and 3509 are divisors of 3509)
3509 / 2 = 1754.5 (the remainder is 1, so 2 is not a divisor of 3509)
3509 / 3 = 1169.6666666667 (the remainder is 2, so 3 is not a divisor of 3509)
...
3509 / 58 = 60.5 (the remainder is 29, so 58 is not a divisor of 3509)
3509 / 59 = 59.474576271186 (the remainder is 28, so 59 is not a divisor of 3509)