What are the divisors of 3527?

1, 3527

There is a total of 2 positive divisors.
The sum of these divisors is 3528.
The arithmetic mean is 1764.

2 odd divisors

1, 3527

How to compute the divisors of 3527?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 3527 by each of the numbers from 1 to 3527 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

3527 / 1 = 3527 (the remainder is 0, so 1 is a divisor of 3527)
3527 / 2 = 1763.5 (the remainder is 1, so 2 is not a divisor of 3527)
3527 / 3 = 1175.6666666667 (the remainder is 2, so 3 is not a divisor of 3527)
...
3527 / 3526 = 1.0002836074872 (the remainder is 1, so 3526 is not a divisor of 3527)
3527 / 3527 = 1 (the remainder is 0, so 3527 is a divisor of 3527)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 3527 (i.e. 59.388551085205). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

3527 / 1 = 3527 (the remainder is 0, so 1 and 3527 are divisors of 3527)
3527 / 2 = 1763.5 (the remainder is 1, so 2 is not a divisor of 3527)
3527 / 3 = 1175.6666666667 (the remainder is 2, so 3 is not a divisor of 3527)
...
3527 / 58 = 60.810344827586 (the remainder is 47, so 58 is not a divisor of 3527)
3527 / 59 = 59.779661016949 (the remainder is 46, so 59 is not a divisor of 3527)