What are the divisors of 3623?

1, 3623

There is a total of 2 positive divisors.
The sum of these divisors is 3624.
The arithmetic mean is 1812.

2 odd divisors

1, 3623

How to compute the divisors of 3623?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 3623 by each of the numbers from 1 to 3623 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

3623 / 1 = 3623 (the remainder is 0, so 1 is a divisor of 3623)
3623 / 2 = 1811.5 (the remainder is 1, so 2 is not a divisor of 3623)
3623 / 3 = 1207.6666666667 (the remainder is 2, so 3 is not a divisor of 3623)
...
3623 / 3622 = 1.0002760905577 (the remainder is 1, so 3622 is not a divisor of 3623)
3623 / 3623 = 1 (the remainder is 0, so 3623 is a divisor of 3623)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 3623 (i.e. 60.191361506449). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

3623 / 1 = 3623 (the remainder is 0, so 1 and 3623 are divisors of 3623)
3623 / 2 = 1811.5 (the remainder is 1, so 2 is not a divisor of 3623)
3623 / 3 = 1207.6666666667 (the remainder is 2, so 3 is not a divisor of 3623)
...
3623 / 59 = 61.406779661017 (the remainder is 24, so 59 is not a divisor of 3623)
3623 / 60 = 60.383333333333 (the remainder is 23, so 60 is not a divisor of 3623)