What are the divisors of 40?

1, 2, 4, 5, 8, 10, 20, 40

There is a total of 8 positive divisors.
The sum of these divisors is 90.
The arithmetic mean is 11.25.

6 even divisors

2, 4, 8, 10, 20, 40

2 odd divisors

1, 5

How to compute the divisors of 40?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 40 by each of the numbers from 1 to 40 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

40 / 1 = 40 (the remainder is 0, so 1 is a divisor of 40)
40 / 2 = 20 (the remainder is 0, so 2 is a divisor of 40)
40 / 3 = 13.333333333333 (the remainder is 1, so 3 is not a divisor of 40)
...
40 / 39 = 1.025641025641 (the remainder is 1, so 39 is not a divisor of 40)
40 / 40 = 1 (the remainder is 0, so 40 is a divisor of 40)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 40 (i.e. 6.3245553203368). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

40 / 1 = 40 (the remainder is 0, so 1 and 40 are divisors of 40)
40 / 2 = 20 (the remainder is 0, so 2 and 20 are divisors of 40)
40 / 3 = 13.333333333333 (the remainder is 1, so 3 is not a divisor of 40)
...
40 / 5 = 8 (the remainder is 0, so 5 and 8 are divisors of 40)
40 / 6 = 6.6666666666667 (the remainder is 4, so 6 is not a divisor of 40)