What are the divisors of 4080?
1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 17, 20, 24, 30, 34, 40, 48, 51, 60, 68, 80, 85, 102, 120, 136, 170, 204, 240, 255, 272, 340, 408, 510, 680, 816, 1020, 1360, 2040, 4080
- There is a total of 40 positive divisors.
- The sum of these divisors is 13392.
- The arithmetic mean is 334.8.
32 even divisors
2, 4, 6, 8, 10, 12, 16, 20, 24, 30, 34, 40, 48, 60, 68, 80, 102, 120, 136, 170, 204, 240, 272, 340, 408, 510, 680, 816, 1020, 1360, 2040, 4080
8 odd divisors
1, 3, 5, 15, 17, 51, 85, 255
How to compute the divisors of 4080?
A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.
Brute force algorithm
We could start by using a brute-force method which would involve dividing 4080 by each of the numbers from 1 to 4080 to determine which ones have a remainder equal to 0.
(where is the integer part of the quotient)
- 4080 / 1 = 4080 (the remainder is 0, so 1 is a divisor of 4080)
- 4080 / 2 = 2040 (the remainder is 0, so 2 is a divisor of 4080)
- 4080 / 3 = 1360 (the remainder is 0, so 3 is a divisor of 4080)
- ...
- 4080 / 4079 = 1.000245158127 (the remainder is 1, so 4079 is not a divisor of 4080)
- 4080 / 4080 = 1 (the remainder is 0, so 4080 is a divisor of 4080)
Improved algorithm using square-root
However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 4080 (i.e. 63.874877690685). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:
(thus, if , then )
- 4080 / 1 = 4080 (the remainder is 0, so 1 and 4080 are divisors of 4080)
- 4080 / 2 = 2040 (the remainder is 0, so 2 and 2040 are divisors of 4080)
- 4080 / 3 = 1360 (the remainder is 0, so 3 and 1360 are divisors of 4080)
- ...
- 4080 / 62 = 65.806451612903 (the remainder is 50, so 62 is not a divisor of 4080)
- 4080 / 63 = 64.761904761905 (the remainder is 48, so 63 is not a divisor of 4080)