What are the divisors of 4339?

1, 4339

2 odd divisors

1, 4339

How to compute the divisors of 4339?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

N mod M = 0

Brute force algorithm

We could start by using a brute-force method which would involve dividing 4339 by each of the numbers from 1 to 4339 to determine which ones have a remainder equal to 0.

Remainder = N ( M × N M )

(where N M is the integer part of the quotient)

  • 4339 / 1 = 4339 (the remainder is 0, so 1 is a divisor of 4339)
  • 4339 / 2 = 2169.5 (the remainder is 1, so 2 is not a divisor of 4339)
  • 4339 / 3 = 1446.3333333333 (the remainder is 1, so 3 is not a divisor of 4339)
  • ...
  • 4339 / 4338 = 1.0002305209774 (the remainder is 1, so 4338 is not a divisor of 4339)
  • 4339 / 4339 = 1 (the remainder is 0, so 4339 is a divisor of 4339)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 4339 (i.e. 65.871086221498). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

D × d = N

(thus, if N D = d , then N d = D )

  • 4339 / 1 = 4339 (the remainder is 0, so 1 and 4339 are divisors of 4339)
  • 4339 / 2 = 2169.5 (the remainder is 1, so 2 is not a divisor of 4339)
  • 4339 / 3 = 1446.3333333333 (the remainder is 1, so 3 is not a divisor of 4339)
  • ...
  • 4339 / 64 = 67.796875 (the remainder is 51, so 64 is not a divisor of 4339)
  • 4339 / 65 = 66.753846153846 (the remainder is 49, so 65 is not a divisor of 4339)