What are the divisors of 5441?

1, 5441

There is a total of 2 positive divisors.
The sum of these divisors is 5442.
The arithmetic mean is 2721.

2 odd divisors

1, 5441

How to compute the divisors of 5441?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 5441 by each of the numbers from 1 to 5441 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

5441 / 1 = 5441 (the remainder is 0, so 1 is a divisor of 5441)
5441 / 2 = 2720.5 (the remainder is 1, so 2 is not a divisor of 5441)
5441 / 3 = 1813.6666666667 (the remainder is 2, so 3 is not a divisor of 5441)
...
5441 / 5440 = 1.0001838235294 (the remainder is 1, so 5440 is not a divisor of 5441)
5441 / 5441 = 1 (the remainder is 0, so 5441 is a divisor of 5441)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 5441 (i.e. 73.76313442364). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

5441 / 1 = 5441 (the remainder is 0, so 1 and 5441 are divisors of 5441)
5441 / 2 = 2720.5 (the remainder is 1, so 2 is not a divisor of 5441)
5441 / 3 = 1813.6666666667 (the remainder is 2, so 3 is not a divisor of 5441)
...
5441 / 72 = 75.569444444444 (the remainder is 41, so 72 is not a divisor of 5441)
5441 / 73 = 74.534246575342 (the remainder is 39, so 73 is not a divisor of 5441)