What are the divisors of 5674?

1, 2, 2837, 5674

There is a total of 4 positive divisors.
The sum of these divisors is 8514.
The arithmetic mean is 2128.5.

2 even divisors

2, 5674

2 odd divisors

1, 2837

How to compute the divisors of 5674?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 5674 by each of the numbers from 1 to 5674 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

5674 / 1 = 5674 (the remainder is 0, so 1 is a divisor of 5674)
5674 / 2 = 2837 (the remainder is 0, so 2 is a divisor of 5674)
5674 / 3 = 1891.3333333333 (the remainder is 1, so 3 is not a divisor of 5674)
...
5674 / 5673 = 1.0001762735766 (the remainder is 1, so 5673 is not a divisor of 5674)
5674 / 5674 = 1 (the remainder is 0, so 5674 is a divisor of 5674)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 5674 (i.e. 75.325958341066). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

5674 / 1 = 5674 (the remainder is 0, so 1 and 5674 are divisors of 5674)
5674 / 2 = 2837 (the remainder is 0, so 2 and 2837 are divisors of 5674)
5674 / 3 = 1891.3333333333 (the remainder is 1, so 3 is not a divisor of 5674)
...
5674 / 74 = 76.675675675676 (the remainder is 50, so 74 is not a divisor of 5674)
5674 / 75 = 75.653333333333 (the remainder is 49, so 75 is not a divisor of 5674)