What are the divisors of 5701?

1, 5701

There is a total of 2 positive divisors.
The sum of these divisors is 5702.
The arithmetic mean is 2851.

2 odd divisors

1, 5701

How to compute the divisors of 5701?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 5701 by each of the numbers from 1 to 5701 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

5701 / 1 = 5701 (the remainder is 0, so 1 is a divisor of 5701)
5701 / 2 = 2850.5 (the remainder is 1, so 2 is not a divisor of 5701)
5701 / 3 = 1900.3333333333 (the remainder is 1, so 3 is not a divisor of 5701)
...
5701 / 5700 = 1.0001754385965 (the remainder is 1, so 5700 is not a divisor of 5701)
5701 / 5701 = 1 (the remainder is 0, so 5701 is a divisor of 5701)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 5701 (i.e. 75.504966724051). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

5701 / 1 = 5701 (the remainder is 0, so 1 and 5701 are divisors of 5701)
5701 / 2 = 2850.5 (the remainder is 1, so 2 is not a divisor of 5701)
5701 / 3 = 1900.3333333333 (the remainder is 1, so 3 is not a divisor of 5701)
...
5701 / 74 = 77.040540540541 (the remainder is 3, so 74 is not a divisor of 5701)
5701 / 75 = 76.013333333333 (the remainder is 1, so 75 is not a divisor of 5701)