What are the divisors of 5818?

1, 2, 2909, 5818

There is a total of 4 positive divisors.
The sum of these divisors is 8730.
The arithmetic mean is 2182.5.

2 even divisors

2, 5818

2 odd divisors

1, 2909

How to compute the divisors of 5818?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 5818 by each of the numbers from 1 to 5818 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

5818 / 1 = 5818 (the remainder is 0, so 1 is a divisor of 5818)
5818 / 2 = 2909 (the remainder is 0, so 2 is a divisor of 5818)
5818 / 3 = 1939.3333333333 (the remainder is 1, so 3 is not a divisor of 5818)
...
5818 / 5817 = 1.0001719099192 (the remainder is 1, so 5817 is not a divisor of 5818)
5818 / 5818 = 1 (the remainder is 0, so 5818 is a divisor of 5818)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 5818 (i.e. 76.2758153021). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

5818 / 1 = 5818 (the remainder is 0, so 1 and 5818 are divisors of 5818)
5818 / 2 = 2909 (the remainder is 0, so 2 and 2909 are divisors of 5818)
5818 / 3 = 1939.3333333333 (the remainder is 1, so 3 is not a divisor of 5818)
...
5818 / 75 = 77.573333333333 (the remainder is 43, so 75 is not a divisor of 5818)
5818 / 76 = 76.552631578947 (the remainder is 42, so 76 is not a divisor of 5818)