What are the divisors of 9614?

1, 2, 11, 19, 22, 23, 38, 46, 209, 253, 418, 437, 506, 874, 4807, 9614

There is a total of 16 positive divisors.
The sum of these divisors is 17280.
The arithmetic mean is 1080.

8 even divisors

2, 22, 38, 46, 418, 506, 874, 9614

8 odd divisors

1, 11, 19, 23, 209, 253, 437, 4807

How to compute the divisors of 9614?

A number N is said to be divisible by a number M (with M non-zero) if, when we divide N by M, the remainder of the division is zero.

$N mod M = 0$

Brute force algorithm

We could start by using a brute-force method which would involve dividing 9614 by each of the numbers from 1 to 9614 to determine which ones have a remainder equal to 0.

$Remainder = N - (M \times ⌊ \frac{N}{M} ⌋)$

(where $⌊ \frac{N}{M} ⌋$ is the integer part of the quotient)

9614 / 1 = 9614 (the remainder is 0, so 1 is a divisor of 9614)
9614 / 2 = 4807 (the remainder is 0, so 2 is a divisor of 9614)
9614 / 3 = 3204.6666666667 (the remainder is 2, so 3 is not a divisor of 9614)
...
9614 / 9613 = 1.0001040257984 (the remainder is 1, so 9613 is not a divisor of 9614)
9614 / 9614 = 1 (the remainder is 0, so 9614 is a divisor of 9614)

Improved algorithm using square-root

However, there is another slightly better approach that reduces the number of iterations by testing only integers less than or equal to the square root of 9614 (i.e. 98.051007134042). Indeed, if a number N has a divisor D greater than its square root, then there is necessarily a smaller divisor d such that:

$D \times d = N$

(thus, if $\frac{N}{D} = d$ , then $\frac{N}{d} = D$ )

9614 / 1 = 9614 (the remainder is 0, so 1 and 9614 are divisors of 9614)
9614 / 2 = 4807 (the remainder is 0, so 2 and 4807 are divisors of 9614)
9614 / 3 = 3204.6666666667 (the remainder is 2, so 3 is not a divisor of 9614)
...
9614 / 97 = 99.113402061856 (the remainder is 11, so 97 is not a divisor of 9614)
9614 / 98 = 98.102040816327 (the remainder is 10, so 98 is not a divisor of 9614)