What is 19 mod 6?

How to compute 19 mod 6?

The simplest approach is to use the "mod" operator (often denoted as "%" in many programming languages), but you could do it manually in the following way:

$\mathrm{Remainder}=N-(M\times \lfloor \frac{N}{M}\rfloor )$

(where N is the dividend, M is the divisor and $\lfloor \frac{N}{M}\rfloor$ represents the integer part of the quotient)

1. 19 / 6 = 3.1666666666667
2. ⌊3.1666666666667⌋ = 3 (We only keep the integer part)
3. 6 × 3 = 18
4. 19 - 18 = 1 (Subtracting gives us the remainder)

In short: 19 − (6 × ⌊19 / 6⌋) = 1

Is 19 divisible by 6?

A number is said to be divisible by another number, if the remainder of the division is zero.

Given that the result of 19 mod 6 is 1, this indicates that dividing 19 by 6 leaves a remainder of 1. Therefore, no, since the remainder isn't zero, 19 is not divisible by 6.