What is 33 mod 7?

How to compute 33 mod 7?

The simplest approach is to use the "mod" operator (often denoted as "%" in many programming languages), but you could do it manually in the following way:

$\mathrm{Remainder}=N-(M\times \lfloor \frac{N}{M}\rfloor )$

(where N is the dividend, M is the divisor and $\lfloor \frac{N}{M}\rfloor$ represents the integer part of the quotient)

1. 33 / 7 = 4.7142857142857
2. ⌊4.7142857142857⌋ = 4 (We only keep the integer part)
3. 7 × 4 = 28
4. 33 - 28 = 5 (Subtracting gives us the remainder)

In short: 33 − (7 × ⌊33 / 7⌋) = 5

Is 33 divisible by 7?

A number is said to be divisible by another number, if the remainder of the division is zero.

Given that the result of 33 mod 7 is 5, this indicates that dividing 33 by 7 leaves a remainder of 5. Therefore, no, since the remainder isn't zero, 33 is not divisible by 7.