What is 41 mod 6?

Often represented by the operator "mod", the modulo is a mathematical operation that gives the remainder of an integer division.

The result of 41 mod 6 is 5.

How to compute 41 mod 6?

The simplest approach is to use the "mod" operator (often denoted as "%" in many programming languages), but you could do it manually in the following way:

Remainder = N − ( M × ⌊ N M ⌋ )

(where N is the dividend, M is the divisor and ⌊ N M ⌋ represents the integer part of the quotient)

  1. 41 / 6 = 6.8333333333333
  2. ⌊6.8333333333333⌋ = 6 (We only keep the integer part)
  3. 6 × 6 = 36
  4. 41 - 36 = 5 (Subtracting gives us the remainder)

In short: 41 − (6 × ⌊41 / 6⌋) = 5

Is 41 divisible by 6?

A number is said to be divisible by another number, if the remainder of the division is zero.

Given that the result of 41 mod 6 is 5, this indicates that dividing 41 by 6 leaves a remainder of 5. Therefore, no, since the remainder isn't zero, 41 is not divisible by 6.