What is 41 mod 9?

How to compute 41 mod 9?

The simplest approach is to use the "mod" operator (often denoted as "%" in many programming languages), but you could do it manually in the following way:

$\mathrm{Remainder}=N-(M\times \lfloor \frac{N}{M}\rfloor )$

(where N is the dividend, M is the divisor and $\lfloor \frac{N}{M}\rfloor$ represents the integer part of the quotient)

1. 41 / 9 = 4.5555555555556
2. ⌊4.5555555555556⌋ = 4 (We only keep the integer part)
3. 9 × 4 = 36
4. 41 - 36 = 5 (Subtracting gives us the remainder)

In short: 41 − (9 × ⌊41 / 9⌋) = 5

Is 41 divisible by 9?

A number is said to be divisible by another number, if the remainder of the division is zero.

Given that the result of 41 mod 9 is 5, this indicates that dividing 41 by 9 leaves a remainder of 5. Therefore, no, since the remainder isn't zero, 41 is not divisible by 9.