What is 47 mod 6?

How to compute 47 mod 6?

The simplest approach is to use the "mod" operator (often denoted as "%" in many programming languages), but you could do it manually in the following way:

$\mathrm{Remainder}=N-(M\times \lfloor \frac{N}{M}\rfloor )$

(where N is the dividend, M is the divisor and $\lfloor \frac{N}{M}\rfloor$ represents the integer part of the quotient)

1. 47 / 6 = 7.8333333333333
2. ⌊7.8333333333333⌋ = 7 (We only keep the integer part)
3. 6 × 7 = 42
4. 47 - 42 = 5 (Subtracting gives us the remainder)

In short: 47 − (6 × ⌊47 / 6⌋) = 5

Is 47 divisible by 6?

A number is said to be divisible by another number, if the remainder of the division is zero.

Given that the result of 47 mod 6 is 5, this indicates that dividing 47 by 6 leaves a remainder of 5. Therefore, no, since the remainder isn't zero, 47 is not divisible by 6.