What is 57 mod 6?

Often represented by the operator "mod", the modulo is a mathematical operation that gives the remainder of an integer division.

The result of 57 mod 6 is 3.

How to compute 57 mod 6?

The simplest approach is to use the "mod" operator (often denoted as "%" in many programming languages), but you could do it manually in the following way:

Remainder = N − ( M × ⌊ N M ⌋ )

(where N is the dividend, M is the divisor and ⌊ N M ⌋ represents the integer part of the quotient)

  1. 57 / 6 = 9.5
  2. ⌊9.5⌋ = 9 (We only keep the integer part)
  3. 6 × 9 = 54
  4. 57 - 54 = 3 (Subtracting gives us the remainder)

In short: 57 − (6 × ⌊57 / 6⌋) = 3

Is 57 divisible by 6?

A number is said to be divisible by another number, if the remainder of the division is zero.

Given that the result of 57 mod 6 is 3, this indicates that dividing 57 by 6 leaves a remainder of 3. Therefore, no, since the remainder isn't zero, 57 is not divisible by 6.