What is 58 mod 7?

Often represented by the operator "mod", the modulo is a mathematical operation that gives the remainder of an integer division.

The result of 58 mod 7 is 2.

How to compute 58 mod 7?

The simplest approach is to use the "mod" operator (often denoted as "%" in many programming languages), but you could do it manually in the following way:

Remainder = N − ( M × ⌊ N M ⌋ )

(where N is the dividend, M is the divisor and ⌊ N M ⌋ represents the integer part of the quotient)

  1. 58 / 7 = 8.2857142857143
  2. ⌊8.2857142857143⌋ = 8 (We only keep the integer part)
  3. 7 × 8 = 56
  4. 58 - 56 = 2 (Subtracting gives us the remainder)

In short: 58 − (7 × ⌊58 / 7⌋) = 2

Is 58 divisible by 7?

A number is said to be divisible by another number, if the remainder of the division is zero.

Given that the result of 58 mod 7 is 2, this indicates that dividing 58 by 7 leaves a remainder of 2. Therefore, no, since the remainder isn't zero, 58 is not divisible by 7.