What is 6 mod 51?

How to compute 6 mod 51?

The simplest approach is to use the "mod" operator (often denoted as "%" in many programming languages), but you could do it manually in the following way:

$\mathrm{Remainder}=N-(M\times \lfloor \frac{N}{M}\rfloor )$

(where N is the dividend, M is the divisor and $\lfloor \frac{N}{M}\rfloor$ represents the integer part of the quotient)

1. 6 / 51 = 0.11764705882353
2. ⌊0.11764705882353⌋ = 0 (We only keep the integer part)
3. 51 × 0 = 0
4. 6 - 0 = 6 (Subtracting gives us the remainder)

In short: 6 − (51 × ⌊6 / 51⌋) = 6

Is 6 divisible by 51?

A number is said to be divisible by another number, if the remainder of the division is zero.

Given that the result of 6 mod 51 is 6, this indicates that dividing 6 by 51 leaves a remainder of 6. Therefore, no, since the remainder isn't zero, 6 is not divisible by 51.