What is 61 mod 2?

How to compute 61 mod 2?

The simplest approach is to use the "mod" operator (often denoted as "%" in many programming languages), but you could do it manually in the following way:

$\mathrm{Remainder}=N-(M\times \lfloor \frac{N}{M}\rfloor )$

(where N is the dividend, M is the divisor and $\lfloor \frac{N}{M}\rfloor$ represents the integer part of the quotient)

1. 61 / 2 = 30.5
2. ⌊30.5⌋ = 30 (We only keep the integer part)
3. 2 × 30 = 60
4. 61 - 60 = 1 (Subtracting gives us the remainder)

In short: 61 − (2 × ⌊61 / 2⌋) = 1

Is 61 divisible by 2?

A number is said to be divisible by another number, if the remainder of the division is zero.

Given that the result of 61 mod 2 is 1, this indicates that dividing 61 by 2 leaves a remainder of 1. Therefore, no, since the remainder isn't zero, 61 is not divisible by 2.